x^2-4x-3.84=0

Solution for x^2-4x-3.84=0 equation:

x^2-4x-3.84=0

a = 1; b = -4; c = -3.84;
Δ = b2-4ac
Δ = -42-4·1·(-3.84)
Δ = 31.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{31.36}}{2*1}=\frac{4-\sqrt{31.36}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{31.36}}{2*1}=\frac{4+\sqrt{31.36}}{2}
$